sql - Select Distinct result on top but return all result -


i have table below structure , data ...

email      name address abc@a.com  ab    abc@a.com  de    fr xyz@x.com  bv    dc efg@e.com  cd    mm xyz@x.com  bv    dc efg@e.com  cd    mm

i want display distinct rows based on email on top. example in above case result should be:

email      name address abc@a.com  ab    xyz@x.com  bv    dc efg@e.com  cd    mm abc@a.com  de    fr xyz@x.com  bv    dc efg@e.com  cd    mm

i using below query me distinct result , need rows distinct on top

select row_number() over(partition email order email desc) rownumber, email, name address rownumber = 1

the easy way... use row_number in order clause...

if object_id('tempdb..#testdata', 'u') not null  drop table #testdata;  create table #testdata (     email varchar(10) not null,     [name] char(2) not null,     [address] char(2) not null      );  insert #testdata (email, [name], [address]) values     ('abc@a.com', 'ab', 'us'),     ('abc@a.com', 'de', 'fr'),     ('xyz@x.com', 'bv', 'dc'),     ('efg@e.com', 'cd', 'mm'),     ('xyz@x.com', 'bv', 'dc'),     ('efg@e.com', 'cd', 'mm');  select     *     #testdata td order      row_number() on (partition td.email order td.[name]);

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