How to write the Array.prototype.every() method in Javascript -

as practice, want write function all() works similar array.prototype.every() method. function returns true if predicate supplied returns true items in array.

array.prototype.all = function (p) {   this.foreach(function (elem) {     if (!p(elem))        return false;   });   return true; };  function isgreaterthanzero (num) {   return num > 0; }  console.log([-1, 0, 2].all(isgreaterthanzero)); // should return false because -1 , 0 not greater 0 

somehow doesn't work , returns true. what's wrong code? there better way write this?

you can't break out of array#foreach loop returning. use loop instead.

note: partial implementation of array#every demonstrate return issue.

array.prototype.all = function (p) {    for(var = 0; < this.length; i++) {      if(!p(this[i])) {        return false;      }    }        return true;  };    function isgreaterthanzero (num) {    return num > 0;  }    console.log([-1, 0, 2].all(isgreaterthanzero));