c - How to make 4 threads interact with each other? -

i have program 4 threads, @ end should print thread , pipeline (2 cycles) stage. like:

thread 2: stage 1 , 2 thread 3: stage 2 , 3 thread 1: stage 3 , 4 thread 4: stage 4 , 5 

but don't know how counter stages because i'm doing can't show stage 1 , 2 each thread, instead of 1 , 2, 2 , 3...

#include <stdio.h> #include <pthread.h> #include <time.h> #include <stdlib.h> #include <unistd.h>  pthread_mutex_t mutex = pthread_mutex_initializer;  void delay (int miliseconds){      long pause;     clock_t now,then;      pause = miliseconds*(clocks_per_sec/1000);     = = clock();     while( (now-then) < pause )         = clock(); }  int print(int n, int parar){      if (n == 5) {         printf("\nestágio 4 e 5");      } else {         printf("estágio %i e %i\n",n, n+1);         if (parar == 2) {             return (n+1, parar+0);         }          return print(n+1, parar+1);     } }  void thread_cont(void *arg){      int *pvalor;     pvalor=arg;      pthread_mutex_lock(&mutex);     printf ("\n---thread %i--- \n", *pvalor);     int = print(1, 1);     delay(2000);     pthread_mutex_unlock(&mutex);  /*     if (*pvalor == 1){         printf ("estágio 1 e 2");     }      if (*pvalor == 2){     printf ("estágio 2 e 3");     }      if (*pvalor == 3){     printf ("estágio 3 e 4");     }      if (*pvalor == 4){     printf ("estágio 4 e 5");     }  */  }  int main() {      pthread_t id1;     int offset1 = 1;     pthread_create(&id1, null, thread_cont, &offset1);      pthread_t id2;     int offset2 = 2;     pthread_create(&id2, null, thread_cont, &offset2);      pthread_t id3;     int offset3 = 3;     pthread_create(&id3, null, thread_cont, &offset3);      pthread_t id4;     int offset4 = 4;     pthread_create(&id4, null, thread_cont, &offset4);      pthread_join(id1, null);     pthread_join(id2, null);     pthread_join(id3, null);     pthread_join(id4, null);      printf("\n");      return 0; } 

i think did wrong explaination question. sorry that, think ended right now. 4 threads. 4 instructions, pipeline(maybe) , didn't used mutex, semaphores. btw language barricade has been made more difficult, ask here.

@edit final , maybe right code

#include <stdio.h> #include <pthread.h> #include <time.h> #include <unistd.h> #include <stdlib.h> #include <semaphore.h>  sem_t mutex; pthread_t id1; pthread_t id2; pthread_t id3; pthread_t id4;  void delay (int miliseconds){      long pause;     clock_t now,then;      pause = miliseconds*(clocks_per_sec/1000);     = = clock();     while( (now-then) < pause )         = clock(); }  pthread_mutex_t lock;  void *thread_cont(void *arg){      int *pvalor;     pvalor=arg;       pthread_mutex_lock(&lock);     sem_wait(&mutex);     printf ("\n---thread %i---", *pvalor);     printf ("stage 1");     delay(2000);       printf ("\n---thread %i---", *pvalor);     printf ("stage 2");     sem_post(&mutex);     pthread_mutex_unlock(&lock);       printf ("\n---thread %i---", *pvalor);     printf ("stage 3");     delay(2000);      printf ("\n---thread %i---", *pvalor);     printf ("stage 4");     delay(2000);      pthread_exit(0);  }   int main(){      //create threads      sem_init(&mutex, 0, 2);   //one each create  int offset1 = 1; int offset2 = 2; int offset3 = 3; int offset4 = 4;       pthread_create(&id1, null, thread_cont, &offset1);           delay(2000);     pthread_create(&id2, null, thread_cont, &offset2);     delay(2000);     pthread_create(&id3, null, thread_cont, &offset3);     delay(2000);     pthread_create(&id3, null, thread_cont, &offset3);     delay(2000);     pthread_create(&id4, null, thread_cont, &offset4);     delay(2000);       pthread_join(id1, null);     pthread_join(id2, null);     pthread_join(id3, null);     pthread_join(id4, null);       sem_destroy(&mutex);      printf("\n");      return 0; }