javascript - Using Ajax to insert data to mysql -


i want insert data mysql using ajax. however, not able save database. can suggest mistakes is?

the html , ajax code below: 

<div class="modal fade" id="addjoint2" role="dialog" action="handle.php">     <table id="01">         <tr>             <th></th>             <th>joint applicant2</th>         </tr>         <tr>             <td>occupation</td>             <td><input type="text" id="occupationjoint2" name="occupationjoint2" type="text" value="<?php echo $occupationjoint2; ?>"></td>         </tr>     </table>           <div class="modal-footer">         <button type="button" class="btn btn-success btn-lg" data-dismiss="modal" style="width: 100%;"><span class="glyphicon glyphicon-ok-sign"></span>insert</button>     </div>   </div>  <script>     $('#addjoint2 button.btn.btn-warning.btn-lg').click(function (event) {         event.preventdefault();         $.ajax({             url: "handle.php", //this submit url             type: 'post', //or             data: $('#addjoint2 form').serialize(),             success: function (data) {                 alert('joint 2 added');                 window.location.reload();              }         });     }); </script>

i not sure id, must same? when put #addjoint2 in ajax, error occurred (when click on field, alert appear).

my handle.php:

<?php session_start(); require_once 'db/dbfunction.php';  $con = open_connection();    function addemployementdetails3($con, $occupationjoint2){     $query2 = "insert employementdetails(occupation)             values('$occupationjoint2')";                   $insertresult2 = mysqli_query($con, $query2);                  if($insertresult2){                      echo " applicant detail added !<br />";                      echo "<a href='index.php'>back home</a>";                  }                  else {                      echo " error !";                      echo "{$query2}";                      //header('location: post.php');                  } }  if (isset($_post['occupationjoint2'])){ $occupationjoint2 = $_post['occupationjoint2'];  addemployementdetails3($con, $occupationjoint2); }   close_connection($con);

put input type inside form , give id form

<form id="addjoint2"> <input type="text" id="occupationjoint2" name="occupationjoint2" type="text" value="<?php echo $occupationjoint2; ?>"> </form> <input type="button" id="btn" value="submit">

and use following jquery value form fields.

<script>     $('#btn').click(function () {          $.ajax({             url: "handle.php", //this submit url             type: 'post', //or             data: $('#addjoint2').serialize(),             success: function (data) {                 alert('joint 2 added');                 window.location.reload();              }         });     }); </script>

later can extract data in target page

$value1=$_post['occupationjoint2'];

after collecting field data this, insert database.


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