python - Only Search the Exact Match -


so, have long list (example truncated) values this:

derp = [[('interface_name', 'interface-1'), ('ip_address', '10.1.1.1'), ('mac_address', 'xx:xx:xx:xx:xx:xx')], [('interface_name', 'interface 2'), ('ip_address', '10.1.1.2'), ('mac_address', 'xx:xx:xx:xx:xx:xx')], [('interface_name', 'interface 3'), ('ip_address', '10.1.1.11'), ('mac_address', 'xx:xx:xx:xx:xx:xx')]]

i have function goes through massive list , pulls out match based on ip problem is, seems match on in last octet , not exact match.

findip = sys.argv[1]  def arpint(arp_info):    val in arp_info:        if re.search(findip, str(val)):            interface = val.pop(0)            string = val            print string, interface[1]  arpint(derp)

so in above case, if findip = '10.1.1.1' come 10.1.1.1 , 10.1.1.11. i'd imagine there has way force input is...

don't use regular expression. string itself.

data = [[('interface_name', 'interface-1'),          ('ip_address', '10.1.1.1'),          ('mac_address', 'xx:xx:xx:xx:xx:xx')],         [('interface_name', 'interface-1a'),          ('ip_address', '010.001.001.001'),          ('mac_address', 'xx:xx:xx:xx:xx:xx')],         [('interface_name', 'interface 2'),          ('ip_address', '10.1.1.2'),          ('mac_address', 'xx:xx:xx:xx:xx:xx')],         [('interface_name', 'interface 3'),          ('ip_address', '10.1.1.11'),          ('mac_address', 'xx:xx:xx:xx:xx:xx')]]   key = '10.1.1.1' interface, ip, mac in data:     if key in ip:         #print(interface, ip)         print([interface, ip, mac], interface[1])

of course works if ip addresses in data conform example ... no leading zeroes.

if addresses might have leading zeros compare integer equivalents of addresses

key = '10.1.1.1' key = map(int, key.split('.')) interface, ip, mac in data:     ip_address = ip[1]     ip_address = map(int, ip_address.split('.'))     if ip_address == key:         #print(interface, ip)         print([interface, ip, mac], interface[1])

i don't have python 3.x on computer don't know if map objects can compared that. if not, use all(a == b a, b in zip(ip_address, key)) condition.


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