Using a 'Where' filter in Jekyll to only return items that are not blank -

i have csv data file contains list of projects. assign variables filtered segments of data - loop through them.

here have tried filter projects show projects have been assigned value in global_priority field. if project has no value not in list.

i have tried using where_exp, returns everything. best way approach this? possible achieve without using if statement?

projects.csv

name,global_priority,region,region_priority project a,1,global, project b,,spain,1 project c,2,uk,1 

the loop

{% assign projects = site.data.projects %} {% assign global_p = projects | where_exp: "item.global_priority", "item.global_priority != blank" %}    {% p in global_p %}     <ul>       <li>{{ p.global_priority }}</li>       <li>{{ p.region }}</li>       <li>{{ p.name }}</li>     </ul>   {% endfor %} 

there small mistake in way access where_exp item, should refer name use in comparation: where_exp: "item"

then:

{% assign global_p = site.data.projects | where_exp: "item", "item.global_priority" %}  {% p in global_p %} <ul>   <li>{{ p.global_priority }}</li>   <li>{{ p.region }}</li>   <li>{{ p.name }}</li>   </ul> {% endfor %} 

outputs:

<ul>   <li>1</li>   <li>global</li>   <li>project a</li>   </ul>  <ul>   <li>2</li>   <li>uk</li>   <li>project c</li>   </ul>