python - Compare Items In A List Of Nested Dicts And Perform Simple Arithmetic Operations -

how can put list "image_list" function measure_accuracy have return number of times actual , predicted same? in case, return 3.

list:

image_list = [   { 'path':'1.jpg', 'actual':{'dog'}, 'predicted':{'dog'} },   { 'path':'2.jpg', 'actual':{'dog'}, 'predicted':{'cat'} },   { 'path':'3.jpg', 'actual':{'cat'}, 'predicted':{'cat'} },   { 'path':'4.jpg', 'actual':{'cat'}, 'predicted':{'dog'} },   { 'path':'5.jpg', 'actual':{'dog'}, 'predicted':{'dog'} } ] 

so want compare each item in list , if if 2 items same add variable in end return variable. not know code there.

i thought maybe like

for actual, predicted in image_list:     if actual == predicted:         count = count + 1 

in [7]: sum(x['actual'] == x['predicted'] x in image_list) out[7]: 3 

so:

def measure_accuracy(image_list):     return sum(x['actual'] == x['predicted'] x in image_list)  total = measure_accuracy(image_list) average = total / len(image_list) 

a brief explanation of what's happening here:

x['actual'] == x['predicted'] 

evaluates either true or false. in python, true == 1 , false == 0, we're getting 1 each time predicted value equal actual value, otherwise 0. our list this:

[1, 0, 1, 0, 1] 

then use sum function add them 3.