Regex for 0 or more of a set where at least one of a subset is mandatory -

i'm using regex in notepad++ (basically pcre syntax) find arbitrary-length runs of set of characters. however, run must contain @ least 1 of subset of characters.

for example, use set [abcdefg] string can contain 0 or more of a, b, c, or d, must contain @ least e, f, or g.

currently i'm using [abcd]*[efg][abcd]* i.e. specifying optional ones before and after mandatory ones. there more concise way specify this? (i'm using sets of diacritics etc. pain modify , use them little possible... string used doesn't render below. use \x{0000} syntax verbose)

[ּֽׁׂׅ֑ׄ]*[ ִ ֶ ַ ֻ][ּֽׁׂׅ֑ׄ]*

shorter , more correct

[a-g]*[efg][a-g]*

plus, bookend whitespace boundary:

(?<!\s)[a-g]*[efg][a-g]*(?!\s)

update hebrew char's

the equivalent literal regex

[ִֶַֻּֽׁׂ֑ׅׄ]*[ִֶַֻ][ִֶַֻּֽׁׂ֑ׅׄ]*  

but doesn't render well.

the better choice convert codepoint notation

[\x{591}\x{5b4}\x{5b6}-\x{5b7}\x{5bb}-\x{5bd}\x{5c1}-\x{5c2}\x{5c4}-\x{5c5}]*[\x{5b4}\x{5b6}-\x{5b7}\x{5bb}][\x{591}\x{5b4}\x{5b6}-\x{5b7}\x{5bb}-\x{5bd}\x{5c1}-\x{5c2}\x{5c4}-\x{5c5}]*

expanded

 [\x{591}\x{5b4}\x{5b6}-\x{5b7}\x{5bb}-\x{5bd}\x{5c1}-\x{5c2}\x{5c4}-\x{5c5}]*   [\x{5b4}\x{5b6}-\x{5b7}\x{5bb}]   [\x{591}\x{5b4}\x{5b6}-\x{5b7}\x{5bb}-\x{5bd}\x{5c1}-\x{5c2}\x{5c4}-\x{5c5}]*