python - Send intermittent status of request before sending actual response -

i have server, takes few minutes process specific request , responds it.

the client has keep waiting response without knowing when complete.

is there way let client know processing status? (say 50% completed, 80% completed), without client having poll status.

without using of newer techniques (websockets, webpush/http2, ...), i've used simplified pushlet or long polling solution http 1.1 , various javascript or own client implementation. if solution doesn't fit in use case, can google 2 names further possible ways.

client sends request, reads 17 bytes (inital http response) , reads 2 bytes @ time getting processing status.

server sends valid http response , during request progress sends 2 bytes of percentage completed, until last 2 bytes "ok" , closes connection.

updated: example uwsgi server.py

 time import sleep  def application(env, start_response):      start_response('200 ok', [])       def working():          yield b'00'          sleep(1)          yield b'36'          sleep(1)          yield b'ok'      return working() 

updated: example requests client.py

import requests  response = requests.get('http://localhost:8080/', stream=true) r in response.iter_content(chunk_size=2):     print(r) 

example server (only use testing :)

import socket time import sleep host, port = '', 8888  listen_socket = socket.socket(socket.af_inet, socket.sock_stream) listen_socket.setsockopt(socket.sol_socket, socket.so_reuseaddr, 1) listen_socket.bind((host, port)) listen_socket.listen(1)  while true:     client_connection, client_address = listen_socket.accept()     request = client_connection.recv(1024)     client_connection.send('http/1.1 200 ok\n\n')     client_connection.send('00')  # 0%     sleep(2)  # work done here     client_connection.send('36')  # 36%     sleep(2)  # work done here     client_connection.sendall('ok')  # done     client_connection.close() 

if last 2 bytes aren't "ok", handle error someway else. isn't beautiful http status code compliance more of workaround did work me many years ago.

telnet client example

$ telnet localhost 8888 trying 127.0.0.1... connected localhost. escape character '^]'. / http/1.1 http/1.1 200 ok  0036okconnection closed foreign host.