convert each sub-dictionary in a nested dictionary to defaultdict in Python - 


 class mydict(dict):         pass   def nest_dict(dct):      dct = mydict(dct)      k, v in dct.items():          if isinstance(v, dict):              dct[k] = mydict(v)              nest_dict(v)      return dct   dct = {'a':{'b':{'c':'d'}}} print(type(nest_dict(dct)['a']['b']))

here's piece of code have now. want covert each sub-dictionary in nested dictionary child class of dict, mydict. however, recursion logic change first level of sub dictionary. how modify recursion function?

you're not updating nested structures properly, try:

def nest_dict(dct):     dct = mydict(dct)     k, v in dct.items():         if isinstance(v, dict):             dct[k] = nest_dict(v)     return dct  dct = {'a': {'b': {'c': 'd'}}} print(type(dct['a']['b']))  # <class 'dict'> my_dct = nest_dict(dct) print(type(my_dct['a']['b']))  # <class '__main__.mydict'>

although i'd advise not extend dict , use collections.mutablemapping instead. on python 3.x it's moved collections.abc.mutablemapping.


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