c++ - overloading operators of builtin types -

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• can overload operators built-in types int or float? 2 answers
• program of power operator in c 1 answer

while writing code syntactic sugar implementation of power-operator known in python , other languages, operator definition ok, expression operand(s) matching operators signature yields error, operators never defined. there way (compiler option) implement new operators builtin types?

#include <iostream> #include <cmath>      template<typename t_float> struct powertmp {     t_float value; };  powertmp<double> operator*(double f) {     return {f}; };  double operator*(double l, powertmp<double> r) {     return std::pow(l, r.value); };  int main() {     std::cout << 10.5 *powertmp<double>{2.0} << '\n';     cout << 10.5 ** 2.0 << '\n'; //error }; 

i using mingw.

edit: clang not support definition of operator.

no, cannot overload operator arguments built-in types. if operator doesn't exist said type.

what can create intermediary type. example:

struct enhanceddouble {     double d; };  struct powprecursor {     double d; };  powprecursor operator*(enhanceddouble b) {     return { b.d }; }  enhanceddouble operator*(enhanceddouble lhs, powprecursor rhs) {     return { std::pow(lhs.d, rhs.d) }; } 

you can sugar little more user defined literal.

enhanceddouble operator""_ed(long double d) {     return { (double)d }; } 

throw in operator<< , can this:

std::cout << 4.0_ed ** 4.0_ed; // prints 256